2y/(y²-8y+5) - 1/(y-5)=
2y/(y-5)(y-3) - 1/(y-5)=
Least common multiple=(y-5)(y-3)
2y-1(y-3) / (y-5)(y-3)=
2y-y+3 / (y-5)(y-3)=
y+3 / (y-5)/y-3)
Answer : (y+3) / (y-5)(y-3).
you did right, congratulations!!.
Answer:
x = log(1+√2) ≈ 0.38277569
Step-by-step explanation:
Let z = 10^x. Then the equation can be rewritten ...
z^2 -2z -1 = 0
z^2 -2z +1 -2 = 0 . . . . rewrite to a form with a square
(z -1)^2 = 2 . . . . . . . . . add 2
z -1 = ±√2 . . . . . . . . . . square root
z = 1 ± √2 . . . . . . . . . . add 1
From the definition of z, we know it must be positive, so the only viable solution here is ...
z = 10^x = 1+√2
x = log(1+√2)
x ≈ 0.38277569
Answer:
it is 70
Step-by-step explanation:
u add all of it and 70 will be your answer
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