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BARSIC [14]
3 years ago
6

A scuba driver is investigating a coral reef 6 meters below sea. If he descends another 21 meters what will be his final locatio

n
Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0

Answer:

-27 meters.

Step-by-step explanation:

The reason for this is that the scuba diver is already currently -6 meters down below sea level. If he goes another -21, the answer would be -27. Adding 2 negative numbers will result in another negative. So -6 + -21 is equal to -27.

tatiyna3 years ago
3 0

Answer:

27 meters

Step-by-step explanation:

please leave brainiest 5 star and thx i really appreciate it

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2.8

The tenths place is right after the decimal, so when we round 2.794 to the nearest tenths place, we get 2.8

Hope this helps! Have a good day :)
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Gina has 48 stickers. of the stickers have pictures of flowers. of the stickers have pictures of plants. The rest of the sticker
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Answer:

A

Step-by-step explanation:

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2 years ago
Rewrite the following equation in slope-intercept form. 18x − 19y = -20
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3 years ago
Divide. Write the quotient in lowest terms. 4\dfrac{2}{3} \div 7 =4 3 2 ​ ÷7=4, start fraction, 2, divided by, 3, end fraction,
velikii [3]

Answer:

\dfrac{2}{3}

Step-by-step explanation:

Given the quotient: 4\dfrac{2}{3} \div 7

Step 1: Write 4\dfrac{2}{3} in improper fraction.

4\dfrac{2}{3}=\dfrac{14}{3}

Therefore:

4\dfrac{2}{3} \div 7=\dfrac{14}{3} \div 7

<u>Step 2:</u> Change the division sign to multiplication by taking the reciprocal of 7

\dfrac{14}{3} \div 7 =\dfrac{14}{3} X\dfrac{1}{7} \\$Simplify\\\\=\dfrac{2}{3}

3 0
2 years ago
A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requi
Vika [28.1K]

Answer:

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 180, \pi = \frac{14}{180} = 0.0778

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 - 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.0387

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 + 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.1169

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

4 0
3 years ago
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