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3 years ago

When I double my number, add three, subtract my number, and subtract one, I get my number plus two.

Mathematics

1 answer:

Umnica [9.8K]3 years ago

8 0

Answer:1=1

Step-by-step explanation:Let your no.= x

double the number=2x

add 4 = 2x+4

subtract same number=2x+4-x

subtract 3=2x+4-x-3

I get my number plus 1=x+1

so equation we get

2x+4-x-3=x+1

x+1=x+1

x=x

it means x is equal to all real number

So your number can be any real number

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New York City is located about 40˚ north of the equator. If Earth's radius is about 4000 miles, approximately how many miles sou

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Answer:

The answer is "2793 miles"

Step-by-step explanation:

In this firstly we convert degrees to radians, which can be defined as follows:

$\to \theta =\frac{40^{\circ} \times \pi }{180^{\circ}}$

$=\frac{ 2\pi }{9}$

Now calculating the distance:

$=\frac{2\pi }{9} \times 4000\\\\= \frac{8000 \pi }{9}$

$=\frac{8000\times 3.14 }{9}\\\\ = \frac{25120}{9}\\\\=2793 \ miles$

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3 years ago

Katy is deciding which charity to donate to. She is going to donate fifty dollars to each charity chosen, and she can donate to

Natasha2012 [34]

Answer:

Step-by-step explanation:

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3 years ago

(4.23)(1.6) please multiple

Wewaii [24]

Answer:

The correct answer is 6.768.

Step-by-step explanation:

(4.23)(1.6) = 6.768

8 0

3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

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4 years ago

NISA [10]

Answer:

Step-by-step explanation:

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3 years ago

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