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Semmy [17]
3 years ago
8

Solve for x sin(x-20) = cos(x)

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

x=\frac{6480^{\circ \:}n+1980^{\circ \:}}{36}

x=\frac{36\pi n+11\pi }{36}

Step-by-step explanation:

We can use the identity: \cos \left(x\right)=\sin \left(90^{\circ \:}-x\right) to simplify this into:\sin \left(x-20^{\circ \:}\right)=\sin \left(90^{\circ \:}-x\right)

The identity sin(x) = sin(y)  -->  x=y+2\pi n,\:x=\pi -y+2\pi n, can be used to simplify this further:

x-20^{\circ \:}=90^{\circ \:}-x+360^{\circ \:}n    (Add 20 to both sides)

x=-x+360^{\circ \:}n+110^{\circ \:}    (Add x to both sides)

2x=360^{\circ \:}n+110^{\circ \:}    (Divide both sides by 2)

\frac{2x}{2}=\frac{360^{\circ \:}n}{2}+\frac{110^{\circ \:}}{2}    (Simplify)

x=\frac{6480^{\circ \:}n+1980^{\circ \:}}{36}    If required, we can convert this into radians:

x=\frac{36\pi n+11\pi }{36}

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