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nexus9112 [7]
3 years ago
10

What is the area? Please help!!!

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer: 96 ft²

Step-by-step explanation:

<u>This figure can be divided into two rectangles:</u>

  • The first rectangle has dimensions 6 ft by 14 ft.
  • The second rectangle had dimensions 4 ft by 3 ft.

<u />

<u>Find the area of both rectangles:</u>

  • The first rectangle: 6 × 14 = 84 ft²
  • The second rectangle: 4 × 3 = 12 ft²

<u />

<u>Add them together to find the total area of the figure:</u>

84 + 12 = 96 ft²

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Dmitriy789 [7]

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Step-by-step explanation:

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3 years ago
Given log630 ≈ 1.898 and log62 ≈ 0.387, log615 =
Tom [10]

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2 years ago
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nirvana33 [79]

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Step-by-step explanation:

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2 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

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3 years ago
I Just Wanna Be Nice And Gice Out A Free Brainliest :D
dolphi86 [110]

Answer:

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