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scoundrel [369]
4 years ago
6

URGENTTTT HELPPPPPPP please

Mathematics
1 answer:
Ahat [919]4 years ago
8 0

Given that ABC is a right triangle.

The length of AC = 10 and AB = 17

We need to determine the m∠B

<u>The measure of ∠B:</u>

The side opposite to ∠B is AC and the hypotenuse of the triangle is AB

The m∠B can be determined using the trigonometric identity,

sin B=\frac{opp}{hyp}

where opp=AC and hyp=AB

Substituting, we get;

sin B=\frac{AC}{AB}

Substituting the values, we get;

sinB=\frac{10}{17}

sin B=0.588

Taking sin^{-1} on both sides of the equation, we have;

B=sin^{-1}(0.588)

B=36.015^{\circ}

Rounding off to the nearest tenth, we get;

B=36.0^{\circ}

Hence, the measure of ∠B is 36.0°

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Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

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=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

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= 10

***************************************************************************************

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5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

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