(AB)^2 + (2 m)^2 = (8 m)^2, or
(AB)^2 + 4 m^2 = 64 m^2, or (AB)^2 = 60 m^2.
Taking the square root of both sides, (length of AB) = + 2sqrt(15) (answer)
Answer:
<u>x = 8√2</u>
Step-by-step explanation:
As the opposing side of the angle and the hypotenuse are given, take the sine ratio of the angle.
- sin 45° = x/16
- 1/√2 = x/16
- x = 16 / √2
- x = 16√2 / 2
- <u>x = 8√2</u>
Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
Answer:
The answer is B, or AD=BC
Step-by-step explanation:
The lengths of the curves do not look similar, as curve BC is longer than curve AD.
Brian will get roughly $16.55.
For this situation you will want to use 0.15 as 15%, and multiply this by the total cost of the bill.
$110.31 x 0.15 = $16.55
