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egoroff_w [7]
3 years ago
15

Nicolas has $6,500 to deposit into an account which earns 3.25% interest compounded annually. How interest will he have earned a

t the end of 8 years.
Mathematics
1 answer:
agasfer [191]3 years ago
7 0

We have been given that Nicolas has $6,500 to deposit into an account which earns 3.25% interest compounded annually. We are asked to find amount of interest earned at the end on 8 years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

3.25\%=\frac{3.25}{100}=0.0325

A=6500(1+\frac{0.0325}{1})^{1\cdot 8}

A=6500(1+0.0325)^{8}

A=6500(1.0325)^{8}

A=6500(1.2915775352963673)

A=8395.253979

Now we will subtract principal amount from final amount to find amount of interest as:

\text{interest}=8395.253979-6500

\text{interest}=1895.253979\approx 1895.25

Therefore, Nicolas would have earned $1895.25 in interest at the end of 8 years.

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Answer:

There are 67626 ways of distributing the chairs.

Step-by-step explanation:

This is a combinatorial problem of balls and sticks. In order to represent a way of distributing n identical chairs to k classrooms we can align n balls and k-1 sticks. The first classroom will receive as many chairs as the amount of balls before the first stick. The second one will receive as many chairs as the amount of balls between the first and the second stick, the third classroom will receive the amount between the second and third stick and so on (if 2 sticks are one next to the other, then the respective classroom receives 0 chairs).

The total amount of ways to distribute n chairs to k classrooms as a result, is the total amount of ways to put k-1 sticks and n balls in a line. This can be represented by picking k-1 places for the sticks from n+k-1 places available; thus the cardinality will be the combinatorial number of n+k-1 with k-1, {n+k-1 \choose k-1} .

For the 2 largest classrooms we distribute n = 50 chairs. Here k = 2, thus the total amount of ways to distribute them is {50+2-1 \choose 2-1} = 51 .

For the 3 remaining classrooms (k=3) we need to distribute the remaining 50 chairs, here we have {50+3-1 \choose 3-1} = {52 \choose 2} = 1326 ways of making the distribution.

As a result, the total amount of possibilities for the chairs to be distributed is 51*1326 = 67626.

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Step-by-step explanation:

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