<h3>
Answer:</h3>
6 hours
<h3>
Step-by-step explanation:</h3>
The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.
That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.
The second hose alone can fill the vat in 6 hours.
_____
The first hose's rate of doing work is ...
... (1 vat)/(12 hours) = (1/12) vat/hour
If h is the second hose's rate of doing work, then working together their rate is ...
... (1/12 vat/hour) + h = (1/4 vat/hour)
... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour
... h = 1/6 vat/hour
so will take 6 hours to fill 1 vat.
Given the equation, S = D/T:
To make the D the subject of the equation, we can start by multiplying both sides by T to isolate D:
(T) S = D/T (T)
TS = D
Therefore, the final answer is D = TS
Answer:
16.2
Step-by-step explanation:
cause. ur a noob at math
You use division
over 2 or 4 or 3 or 5 or 7 and so on
in this case 2 is good
64 = 2 * 2 * 2 * 2 * 2 * 2 ( use division) = 2^6
16 = 2 * 2 * 2 * 2 = 2^4
number reminder
64 0
32 0
16 0
8 0
4 0
2 0
1 1
so 64 = 2^6 (number of zeros) no reminder
