All categories

2 years ago

Veronica has been wanting to learn to ice skate for years!

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

3 0

Answer:

25.45 per lesson

Step-by-step explanation:

divide $305.40 by 12

You might be interested in

Un rectangulo de madera se uso para en marcar un espejo en forma de rombo.Si los lados del marco miden 80.5 cm y 36.4, y las dia

QveST [7]

Answer:

1465.1 cm²

Step-by-step explanation:

El espejo en forma de diamante tiene la forma de rombo

Tenga en cuenta que: las diagonales del rombo tienen las mismas medidas de esos lados

Por lo tanto, el área del espejo se calcula como:

1/2 × Diagonal 1 × Diagonal 2

Diagonal 1 = 80.5 cm

Diagonal 2 = 36.4 cm

= 1/2 × 80.5 cm × 36.4 cm

= 2930.2 cm² / 2

= 1465.1 cm²

Por tanto, el área del espejo es 1465.1 cm².

8 0

2 years ago

NEED ANSWER ASAP!

sveta [45]

Answer:

the answer is c

4.5feets

30 feets

7 0

2 years ago

A restaurant served 5 tuna sandwiches for every 2 egg salad

joja [24]

Answer:

A) 5 + 2 =7 x 4= 28

B) 8

Step-by-step explanation:

A) 5 x 4 = 20 and 2 x 4 = 8 so you add 20 + 8 and you get 28

B) so 5 x 4 is 20 and there is 8 left over and if you do 2 x 4 you get 8

5 0

2 years ago

Please Help!

vovikov84 [41]

Answer:

Step-by-step explanation:

We can use triangle inequality, let AC = x:

x+4 > 5

x+5 > 4

9 > x

Simplifying:

x>1

x>-1

9>x

Thus: 9>x>1

So the Largest whole number is 8

3 0

3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers