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Trava [24]
3 years ago
10

Explain how you would use the Commutive Property of Multiplication to answer 7×3

Mathematics
2 answers:
Fed [463]3 years ago
8 0
7x3=3x7 because you can multiply it in any order the answer
Nookie1986 [14]3 years ago
3 0
ANSWER= 7x3 is still the same as 3x7 so,

7x3=3x7
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Please help! I will mark you as brainliest!
Step2247 [10]

Answer:

{5}^{18}  \:

Step-by-step explanation:

{ \: ( {5}^{3}) }^{6}  =  {5}^{18}

8 0
3 years ago
Read 2 more answers
Find the zero of the function by rewriting the function in intercept form
Marat540 [252]
Given a quadratic function
y = 4x² - 19x - 5
or i will write it as
4x² - 19x - 5 = y

Zero of the function is when y have the value of zero.
So the quadratic equation will be
4x² - 19x - 5 = y
4x² - 19x - 5 = 0

Now make the equation to intercept form by factorization
4x² - 19x - 5 = 0
(4x + 1)(x - 5) = 0   (this is intercept form)

Solution 1
4x + 1 = 0
4x = -1
x = -1/4

Solution 2
x - 5 = 0
x = 5

SUMMARY
-1/4 and 5 are zero function of f(x) = 4x² - 19x - 5
4 0
4 years ago
At a sports store near snow summit are on sale for $476. if the original price was $560, what discount rate does this represent?
Nezavi [6.7K]
560-476=84; 84/560=.15 so 15%
8 0
3 years ago
Name the relationship: altérnate interior, corresponding, or altérnate exterior.
Furkat [3]
The answer is A. Alternate exterior
5 0
3 years ago
Read 2 more answers
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
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