The answer is B.
ln both sides to clear the 'e' and bring 'a' out of the power.
Answer:
19.2
Step-by-step explanation:
Cosine rule :
c will always be the hypotenuse.
a and b can be any if the opposite or the adjacent.
\sqrt{369}=19.20937...
Hey there! :)
Answer:
y = -3x - 11
Step-by-step explanation:
Use the formula y = mx + b to write an equation, where:
y = y-coordinate of point
x = x-coordinate of point
m = the slope
Plug in the known coordinates and slope:
4 = -3(-5) + b
Simplify:
4 = 15 + b
4 - 15 = b
-11 = b
Rewrite the equation:
y = -3x - 11
1. true
2. true
3. true, because the absolute value can never be negative..
4. false ( if wrong then the question wasnt that specific to me, sorry)
5. true...
if im wrong you have the right to be mad, but to me I feel 90% right about the answers...sorry
Answer:
ΔGJH ≅ ΔEKF
HL: GH and EF
SAS: FK and JH (or GH and EF)
ASA: ∠JGH and ∠FEK (or ∠EFK and ∠JHG)
ΔGFJ ≅ ΔEKH
SSS: KH and FJ
SAS: ∠KEH and ∠FGJ
Step-by-step explanation:
List whatever angles/sides need to be congruent for the two triangles to be congruent.
Prove ΔGJH ≅ ΔEKF using....
- HL (Hypotenuse + Leg)
We already have two legs that are congruent (EK and GJ), so we just need the hypotenuses (GH and EF) to be equal.
- SAS (Side + Angle + Side)
1 pair of sides (EK and JG) are equal, and m∠EKF = m∠GJH. So we need one more side. You can either use FK and JH or GH and EF.
- ASA (Angle + Side + Angle)
1 pair of angles (∠EKF and ∠GJH) are already given as equal, and 1 pair of sides (EK and GJ) are equal. We just need one more pair of angles. So either ∠JGH and ∠FEK or ∠EFK and ∠JHG.
Prove ΔGFJ ≅ ΔEKH using...
- SSS (Side + Side + Side)
Two pairs of sides (EK + GJ and EH + FG) are equal, so KH and FJ need to be equal.
- SAS (Side + Angle + Side)
FG + EH and KE + GJ are equal. We need to use the angle in between them to use SAS, so ∠KEH and ∠FGJ need to be equal.
