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11111nata11111 [884]
3 years ago
7

(-2r^3p^2m)^3 I need help with this equation can anyone help?

Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

-8r^9p^6m^3

Step-by-step explanation:

(-2r^3p^2m)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}\\\\\left(-2r^3p^2m\right)^3=-\left(2r^3p^2m\right)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a\times\:b\right)^n=a^nb^n\\\\\left(2r^3p^2m\right)^3=2^3\left(r^3\right)^3\left(p^2\right)^3m^3\\\\=-2^3\left(r^3\right)^3\left(p^2\right)^3m^3\\\\2^3=8\\=-8\left(r^3\right)^3\left(p^2\right)^3m^3\\\\\mathrm{Simplify\:}\left(r^3\right)^3:\quad r^9\\\\=-8r^9\left(p^2\right)^3m^3

\mathrm{Simplify\:}\left(p^2\right)^3:\quad p^6\\\\=-8r^9p^6m^3

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baherus [9]
Yes, (1,7) is a solution.
(x,y)

y < x + 8
y ≤ 6x + 1

7<1+8 = 7<9 Yes, true.
7≤6(1)+1 = 7≤ 7 Yes, true.


Yes, (1,7) is a solution to the inequalities.
8 0
3 years ago
What is the factored form of the function f(x)=x^3+8x^2+5x−50?
Inga [223]

Answer:

the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function f(x)=x^3+8x^2+5x-50

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of x^3+8x^2+5x-50 by (x-2) to find other factors

The long division is shown in figure attached.

After long division we get: x^2+10x+25

The equation x^2+10x+25 can be further simplified as: (x+5)(x+5) or (x+5)^2

So, the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

3 0
3 years ago
Which is the best estimate for the average rate of change for the quadratic function graph on the interval 0 ≤ x ≤ 4?
den301095 [7]
ANSWER

A) -1

EXPLANATION

The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).

That is the average rate of change is:

= \frac{f(4) - f(0)}{4 - 0}

From the graph, f(0) is 0 and f(4) is -4.

We plug in these values to obtain;

= \frac{ - 4 - 0}{4 - 0}

This simplifies to;

= \frac{ - 4}{4}

= - 1

Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
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3 years ago
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zubka84 [21]

Answer:

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Step-by-step explanation:

4x^2 − 32

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7 0
4 years ago
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Answer:

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hope it helped

4 0
3 years ago
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