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11111nata11111 [884]
2 years ago
7

(-2r^3p^2m)^3 I need help with this equation can anyone help?

Mathematics
1 answer:
kozerog [31]2 years ago
4 0

Answer:

-8r^9p^6m^3

Step-by-step explanation:

(-2r^3p^2m)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}\\\\\left(-2r^3p^2m\right)^3=-\left(2r^3p^2m\right)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a\times\:b\right)^n=a^nb^n\\\\\left(2r^3p^2m\right)^3=2^3\left(r^3\right)^3\left(p^2\right)^3m^3\\\\=-2^3\left(r^3\right)^3\left(p^2\right)^3m^3\\\\2^3=8\\=-8\left(r^3\right)^3\left(p^2\right)^3m^3\\\\\mathrm{Simplify\:}\left(r^3\right)^3:\quad r^9\\\\=-8r^9\left(p^2\right)^3m^3

\mathrm{Simplify\:}\left(p^2\right)^3:\quad p^6\\\\=-8r^9p^6m^3

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Step-by-step explanation:

Let me take a guess

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2 years ago
a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream
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<u>Step-by-step explanation:</u>

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ f(x)-g(x)=0

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⇒ 3x^2- 24x + 39-3x + 15  =0

⇒ 3x^2- 27x + 54  =0

⇒ x^2- 9x + 18  =0

⇒ x^2- 6x-3x + 18  =0

⇒ x(x- 6)-3(x - 6)  =0

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⇒ x=3 , x=6

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is (3,-6) and (6,3) .

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Step-by-step explanation:

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