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11111nata11111 [884]
3 years ago
7

(-2r^3p^2m)^3 I need help with this equation can anyone help?

Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

-8r^9p^6m^3

Step-by-step explanation:

(-2r^3p^2m)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}\\\\\left(-2r^3p^2m\right)^3=-\left(2r^3p^2m\right)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a\times\:b\right)^n=a^nb^n\\\\\left(2r^3p^2m\right)^3=2^3\left(r^3\right)^3\left(p^2\right)^3m^3\\\\=-2^3\left(r^3\right)^3\left(p^2\right)^3m^3\\\\2^3=8\\=-8\left(r^3\right)^3\left(p^2\right)^3m^3\\\\\mathrm{Simplify\:}\left(r^3\right)^3:\quad r^9\\\\=-8r^9\left(p^2\right)^3m^3

\mathrm{Simplify\:}\left(p^2\right)^3:\quad p^6\\\\=-8r^9p^6m^3

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