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kondaur [170]
3 years ago
5

How do I do number 14?

Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0
Answer answer answer

luda_lava [24]3 years ago
3 0

Answer:

1/4^3 = 1/64

Step-by-step explanation:

you just basically multiply 1/4 for the first 3 ones, you multiply \frac{1}{4} x\frac{1}{4} x\frac{1}{4} = \frac{1}{64}. then you do the same but twice and then once.

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Solve for x in simplest radical form. 2x2 + 2x + 4 = x2 + 6x + 5
devlian [24]

Answer:

x= √2 - 2 + √5-4√2, √2-2 - √5-4 √2



7 0
3 years ago
Jane needs to solve for the value of n in the equation 10 n = 150. Which of these steps would BEST help Jane solve the equation?
Hoochie [10]

Answer:

n = 15

Step-by-step explanation:

10 x 15 = 150.

<em>Hope this helps!</em>

8 0
2 years ago
How to find the area
Virty [35]

Just like you drew those dotted lines. You know how to find the areas of rectangles which is A=length x width

The answer would be 20cm^2+6cm^2+18cm^2=44 cm^2


7 0
3 years ago
Read 2 more answers
HELP PLEASE ASAP
Vladimir79 [104]

By using dimensional analysis, this problem can be simple.


100cm * \frac{1m}{100cm} = 1m

B

4 0
3 years ago
Can someone help me please
kifflom [539]

9514 1404 393

Answer:

  {Segments, Geometric mean}

  {PS and QS, RS}

  {PS and PQ, PR}

  {PQ and QS, QR}

Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

  short leg : long leg = SP/RS = RS/SQ   ⇒   RS² = SP·SQ

  short leg : hypotenuse = RP/PQ = PS/RP   ⇒   RP² = PS·PQ

  long leg : hypotenuse = RQ/QP = QS/RQ   ⇒   RQ² = QS·QP

I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.

__

  segments PS and QS, gm RS

  segments PS and PQ, gm PR

  segments PQ and QS, gm QR

4 0
2 years ago
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