Three lines given -- it's a natural for the cos(theta) law. A small hint: I think the preferred way of doing it is to use the cos(theta) law twice. It will give you a definite answer.
Find G first
g = 6 yd
h = 7 yd
f = 5 yards.
g^2 = h^2 + f^2 - 2*h*f*cos(G)
6^2 = 7^2 + 5^2- 2*7*5*cos(G)
36 = 49 + 25 - 70*Cos(G)
36 = 74 - 70*cos(G)
-48 = - 70 * cos(G) Divide by -70
-38/-70 = cos(G)
0.5429 = cos(G)
cos-1(0.5429) = G
G = 57.12
Now find H
h^2 = g^2 + f^2 - 2*g*f*cos(H)
7^2 = 5^2 + 6^2 - 2*5*6*cos(H)
49 = 25 + 36 - 60cos(H)
49 =61 - 60*cos(H)
Cos(H) = -12 / - 60
Cos(H) = 0.2
H = cos-1(0.2)
H = 78.46
F can be found because every triangle has 180 degrees
F + 78.46 + 57.12 = 180
F + 135.58 = 180
F = 180 - 135.58
F = 44.41
A <<<< Answer.
The model is 3 inches, since 3 times 3 is 9 and 1 times 3 is 3.
So - first you gotta put it in the y = mx + b form.
4Y = 3X +8
=> y = 4/3X + 1/2
A parallel line has the same slope. So if 3X - 4Y + 8=0 has a slope of 4/3 then the value of K must also be 4/3
Answer:
no solution
Step-by-step explanation:
24 + 6k < -6(-4-k)
Distribute
24+6k< 24 +6k
Subtract 6k from each side
24 < 24
This is never true so there are no solutions
Answer:
1½ mile
Step-by-step explanation:
Given
3/10 mile = ⅕ hour
Required
Determine the distance in 1 hour
Since rate is constant, we have:
3/10 mile = ⅕ hour
Multiply both sides by 5
5 * 3/10 mile = ⅕ hour * 5
15/10 mile = 5/5 hour
3/2 mile = 1 hour
1½ mile = 1 hour
Hence,the child will walk 1½ mile in 1 hour
