mass AsCl₃ in 8.2x10⁵ L = 99.2gAsCl₃
Let's remember that 0.05 ppm (parts per million) would be write terms of mg/L. We have 0.05 mg/L, that is a concentration unit.
First of all we need to find the g/L of AsCl₃ present in water.
Now, we just need to multiply it by 8.2 x 10⁵ L to determine the mass of AsCl₃ present in that volume.
Finally we have:
Have a nice day!
125 – 25 + 5 – 1=105
I hope this helped :))
1379.31meters is the line-of-sight distance from the television camera to the base of the stadium .
A blimp provides aerial television views of a tennis game.
The television camera sights the stadium at a 17degrees angle of depression. The altitude of the blimp is 400m.
Now by using the trignometric identity .
As the figure is given below .
Perpendicular = AC = 400 m
Hypotenuse = AB
Putting all the values in the identity .
AB = 1379.31 meters
Therefore the 1379.31 meters is the line-of-sight distance from the television camera to the base of the stadium .
ax^2 + bx + c = 0
This is the general form of a quadratic polynomial.
as per this,
a = 1
b = 1
c = -3