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soldier1979 [14.2K]
3 years ago
9

Joey had 26 game cards. His friend Richard gave him some more, and now Joey has 100 cards. How many cards did Richard give to Jo

ey?
Mathematics
1 answer:
Roman55 [17]3 years ago
3 0

Given:

Joey had 26 game cards.

His friend Richard gave him some more, and now Joey has 100 cards.

To find:

How many cards did Richard give to Joey?

Solution:

Let x be the number of cards that Richard give to Joey.

Joey had 26 game cards.

Now, the total cards joey has =26+x

Joey has total 100 cards.

26+x=100

x=100-26

x=74

Therefore, Richard gave him 74 cards.

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Since the calculated F=  2.8657 does not lie in the critical region  F (2,2)≥ 19 we conclude that there no difference between the means.

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                            Mean    Standard Deviation Sample Size

Never

Played Football 7602.5          1074                   25

FB with no History   6459.2         779.9                  25

<u>FB with Concussion 5734.6       593.4                   25 </u>

<u>Total                 6598.8      1133.5                  75 </u>

<u />

Anova: Two-Factor Without Replication    

   

SUMMARY Count Sum Average Variance

Row 1 2 8676.5 4338.25 21310656.13

Row 2 2 7239.1 3619.55 16127224.25

Row 3 2 6328 3164 13215968.72

   

Column 1 3 19796.3 6598.766667 886871.7433

Column 2 3 2447.3 815.7666667 58708.90333

<u>ANOVA Table </u>  

Source           Sum of     Degrees     Mean

of Variation      Square    of freedom  Squares

<u>                             SS     df          MS              F P-value </u>

B/w Rows 1401945.703 2 700972.8517 2.8657 0.259

B/w Col      50164633.5 1 50164633.5 205.0819  0.00484

<u>Error     489215.59         2 244607.795                           </u>

Total 52055794.79 5    

Set up the null and alternate hypotheses :

H0 ; there's no difference between the means and

there's no difference between the standard deviations

against the claim

Ha: there's a difference between the means and

there's  a difference between the standard deviations

The significance level is chosen at 0.05

The test statistics to use are

F1= estimated variance from Between Means/  estimated variance from Error SS

F1= s1²/s3²

F1= estimated variance from Between Standard Deviations /  estimated variance from Error SS

F2- s2²/s3²

with υ1= (2,2)  and υ2(1,2) degrees of freedom.

The critical regions for F (2,2)≥ 19 for 0.05 significance level

and F(1,2) ≥ 18.51  for 0.05 significance level

Since the calculated F=  2.8657 does not lie in the critical region  F (2,2)≥ 19 we conclude that there no difference between the means.

Since the calculated F=  205.0819  lies in the critical region F(1,2) ≥ 18.51  we conclude that there is a difference between the standard deviations of the three groups.

The F- statistic for the observed data is 0.101  as calculated by F- test in excel.

7 0
2 years ago
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