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marta [7]
3 years ago
15

Jeff is buying apples and bananas from the farmer's market. He know that to find his total cost he will use the expression 1.25a

+ 0.50b, where a stands for the number of apples he bought and b stands for the number of bananas he bought. If he buys 4 apples and 6 bananas how much money did he spend?
A) $10.00
B) $2.00
C) $7.00
D) $8.00
Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer: 8.00


Step-by-step explanation:

1.25a=3 0.50=5 so the answer is D, 8.00

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Answer:

4:1

Step-by-step explanation:

just divide by the highest numbe 2 in this case

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3 years ago
Help, this is a khan question so you may have done it before
Readme [11.4K]

Answer:

Eric, 9.8 meters.

Step-by-step explanation:

Use the distance formula with the given coordinate and each of the other coordinate.

\sqrt{(10-3)^{2}+(8-2)^{2} } Brooke

\sqrt{(-6-3)^{2}+(6-2)^{2} } Eric

\sqrt{(8-3)^{2}+(-6-2)^{2} } Cam

You'll see that Eric kicked the furthest distance with a distance of 9.8 meters.

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8 0
3 years ago
You roll two six-sided dice. Match each event with its probability.
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Answer:

A) probability the sum is 8 or 11= 4/21

B) probability that sum is 12 or less than 10 = 6/7

C) Probability that the sum is 3 or less than 3 = 2/21

D) Probability that the sum is 2 or 10 = 1/7

Step-by-step explanation:

Since we have the same probability of each event in each dice, the answer would be just to check the different outcomes, two dices, each with 1 to 6;

(1,1);(1,2);(1,3);(1,4);(1,5);(1,6);(2,2);(2,3);(2,4);(2,5);(2,6);(3,3);(3,4);(3,5);(3,6);(4,4);(4,5);(4,6);(5,5);(5,6);(6,6)

Thus, there are 21 possible outcomes.

Now,

A) probability that the sum is 8 or 11;

From the outcomes above, the number of outcomes that have a sum as 8 or 11 are;

(2,6) ; (3,5) ; (4,4) ; (5,6)

So,probability = 4/21

B) From the outcomes above, the number of outcomes that are 12 or less than 10 are;

(1,1);(1,2);(1,3);(1,4);(1,5);(1,6);(2,2);(2,3);(2,4);(2,5);(2,6);(3,3);(3,4);(3,5);(3,6);(4,4);(4,5);(6,6).

There are 18 possible outcomes.

So, probability that sum is 12 or less than 10 = 18/21 = 6/7

C)From the initial 21 outcomes, the number of outcomes that the sum is 3 or less than 3 are;(1,1);(1,2)

Thus,

Probability that the sum is 3 or less than 3 = 2/21

D) From the initial 21 outcomes, the number of outcomes that the sum is 2 or 10 are;

(1,1); (4,6) ; (5,5)

Thus,

Probability that the sum is 2 or 10 = 3/21 = 1/7

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A + B + C = 180
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