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4 years ago

What is the value of f(x)=-3.25x 22.41 at x=-4.2

Mathematics

1 answer:

Gennadij [26K]4 years ago

4 0

F(x)=-3.25x +22.41
f(-4.2)= 3.25(-4.2)+22.41 = 8.76

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How many whole numbers are between 1 and 50 that are divisible by 2?

kupik [55]

Answer:

Step-by-step explanation:

The first number in the range 1 - 50 that is divisible by 2 is 2 itself. Then 4, 6, 8, ....

Here's one way to think and count:

$2 \rightarrow 1\\4 \rightarrow 2\\6 \rightarrow 3\\8 \rightarrow 4\\\vdots\\50\rightarrow 25$

In the table, the number on the right is <u>half</u> the number on the left. The numbers on the right are just counting numbers (natural numbers), so there are 25 even numbers between 1 and 50.

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3 years ago

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A nut mixture of peanuts and macadamia nuts at a small fair is $1.00 per pound of peanuts and $3.26 per pound of macadamia nuts.

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Answer:

Step-by-step explanation:

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3 years ago

How many solutions does a system of equations have when solving results in the statement 3 = 5?

blagie [28]

There would be no solutions

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3 years ago

An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th

lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

$P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}$

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

$P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}$

Finally, the probability of picking two balls of the same colour is

$P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}$

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3 years ago

Pretty please can you help with problem 7. (ONLY IF YOU KNOW)

Vika [28.1K]

1 yard = 3 foot. 1 Foot = 12 inches.
She has 2 yards, 3 inches which = 6 foot 3 inches.
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She has more than enough, and to work out how much she has left -
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3 years ago

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