The perimeter of the triangle is: (9.5n - 11.6p - 3.5q) cm.
<h3>What is the Perimeter of a Triangle?</h3>
The total length of all the sides of a triangle is equal to the perimeter of the triangle.
Given a triangle has the following lengths:
- (2.9n-7.8p) centimeters,
- (6.6n-6.4q) centimeters,
- (2.9q-3.8p) centimeters.
The perimeter of the triangle = (2.9n-7.8p) + (6.6n-6.4q) + (2.9q-3.8p)
The perimeter of the triangle = 2.9n - 7.8p + 6.6n - 6.4q + 2.9q - 3.8p
Combine like terms together
The perimeter of the triangle = 2.9n + 6.6n - 7.8p - 3.8p - 6.4q + 2.9q
The perimeter of the triangle = 9.5n - 11.6p - 3.5q
Thus, the perimeter of the triangle is: (9.5n - 11.6p - 3.5q) cm.
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None of those is. The expression 4 In x + In 3 – In r
is equivalent to the epression <em>ln( 3x⁴ / r)</em> .
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
<h2>
Answer:</h2>
By process of elimination, we can eliminate:
- <em>A:</em> <em>y = 3x - 1</em>
- <em>C: y = 3x + 1</em>
- <em>B: y = -3x</em>
<em>A and C</em> don't work because the given line has it's y-intercept at the origin, therefore, no y-intercept is written. <em>B </em>is not it either because the line <em>does not</em> go <em>down</em> from <em>left to right</em>, therefore, the slope is <em>not</em> negative.
The answer is <em>D: y = 3x</em> because since the line goes <em>up</em> from <em>left to right</em>, the slope is positive, and the y-intercept is the origin, so the equation will have no b.
