<h2>
Answer: The drag force goes up by a factor of 4</h2>
Explanation:
The Drag Force equation is:
(1)
Where:
is the Drag Force
is the Drag coefficient, which depends on the material
is the density of the fluid where the bicycle is moving (air in this case)
is the transversal area of the body or object
the bicycle's velocity
Now, if we assume
,
and
do not channge, we can rewrite (1) as:
(2)
Where
groups all these coefficients.
So, if we have a new velocity
, which is the double of the former velocity:
(3)
Equation (2) is written as:
![F_{D}=C.V_{n}^{2}=C.(2V)^{2}](https://tex.z-dn.net/?f=F_%7BD%7D%3DC.V_%7Bn%7D%5E%7B2%7D%3DC.%282V%29%5E%7B2%7D)
(4)
Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.
Answer:
Explanation:
Since the wires attract each other , the direction of current will be same in both the wires .
Let I be current in wire which is along x - axis
force of attraction per unit length between the two current carrying wire is given by
x ![\frac{2 I_1\times I_2}{d}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20I_1%5Ctimes%20I_2%7D%7Bd%7D)
where I₁ and I₂ are currents in the wires and d is distance between the two
Putting the given values
285 x 10⁻⁶ = 10⁻⁷ x ![\frac{2\times25.5\times I_2}{.3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Ctimes25.5%5Ctimes%20I_2%7D%7B.3%7D)
I₂ = 16.76 A
Current in the wire along x axis is 16.76 A
To find point where magnetic field is zero due the these wires
The point will lie between the two wires as current is in the same direction.
Let at y = y , the neutral point lies
k 2 x
= k 2 x ![\frac{25.5}{.3-y}](https://tex.z-dn.net/?f=%5Cfrac%7B25.5%7D%7B.3-y%7D)
25.5y = 16.76 x .3 - 16.76y
42.26 y = 5.028
y = .119
= .12 m
Answer:
The height of father = 178 cm.
Explanation:
The height of your father is 70 inches.
There are 2.54 centimeters in an inch
1 inch = 2.54 cm
70 inches = 70 x 2.54 = 177.8 cm
Rounding to the nearest centimeter.
70 inches = 177.8 cm = 178 cm
The height of father = 178 cm.
Answer:
The pressure is ![P= - 6.39*10^8Pa](https://tex.z-dn.net/?f=P%3D%20-%20%206.39%2A10%5E8Pa)
The temperature is ![T =1218.63 K](https://tex.z-dn.net/?f=T%20%3D1218.63%20K)
Explanation:
Generally Gibbs free energy is mathematically represented as
![G = E + PV -TS](https://tex.z-dn.net/?f=G%20%3D%20E%20%2B%20PV%20-TS)
Where E is the enthalpy
PV is the pressure volume energy (i.e PV energy)
S is the entropy
T is the temperature
For stability to occur the Gibbs free energy must be equal to zero
Considering Diamond
So at temperature of T = 300 K
![E + PV - TS = 0](https://tex.z-dn.net/?f=E%20%2B%20PV%20-%20TS%20%3D%200)
making P the subject
![P = \frac{TS-E}{V}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BTS-E%7D%7BV%7D)
Now substituting 300 K for T , 2900 J for E ,
for V and
for S
![P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B%28300%20%2A%202.38%29-%202900%7D%7B3.42%2A10%5E%7B-6%7D%7D)
![P= - 6.39*10^8Pa](https://tex.z-dn.net/?f=P%3D%20-%20%206.39%2A10%5E8Pa)
The negative sign signifies the direction of the pressure
Given that ![P = 1*0^5Pa](https://tex.z-dn.net/?f=P%20%3D%201%2A0%5E5Pa)
making T the subject
![T = \frac{PV+E}{S}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7BPV%2BE%7D%7BS%7D)
Substituting into the equation
![T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%2A10%5E5%20%2A%203.42%20%2A10%5E%7B-6%7D%2B2900%7D%7B2.38%7D)
![T =1218.63 K](https://tex.z-dn.net/?f=T%20%3D1218.63%20K)