4 years ago

What is the area of this figure?

1 answer:

5 0

Each little square is 1 inch high and 1 inch wide, so
the area of each little square is 1 square inch.

The bug figure is made of 23 little squares, so the area
of the big figure is 23 square inches.

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Granola bars: y = 3 x. A 2-column table with 4 rows. Column 1 is labeled Guests with entries 3, 6, 9, 12. Column 2 is labeled To

elena55 [62]

Answer:

I think it is toy cars but i am not sure

Step-by-step explanation:

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Is 0.018 a reasonable answer for 1.8x100

Sloan [31]

Answer:

Step-by-step explanation:

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Find the area of a perfect polygon that has 99 sides and each side measures 31 inches

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Step-by-step explanation:

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2 years ago

Simplify. 3a + 2b - 8a + b 11a+ 3b 5a+3b -5a+3b -11a + 2b

german

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4 years ago

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Finding the average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11

krok68 [10]

Answer:

The average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11) is 0.

Step-by-step explanation:

Given a function y, the average rate of change S of $y=g(z)$ in an interval $(z_{s}, z_{f})$ will be given by the following equation:

$S = \frac{g(z_{f}) - g(z_{s})}{z_{f} - z_{s}}$

In this problem, we have that:

$g(z) = 4z^{2} - 5$

Between the points( -2,11) and (2,11).

So $z_{f} = 2, z_{s} = -2$

$g(z_{f}) = g(2) = 4*(2)^{2} - 5 = 11$

$g(z_{s}) = g(-2) = 4*(-2)^{2} - 5 = 11$

$S = \frac{g(z_{f}) - g(z_{s})}{z_{f} - z_{s}} = \frac{11 - 11}{2 - (-2)} = \frac{0}{4} = 0$

The average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11) is 0.

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3 years ago