To find the mean, add all of the numbers together and divide by however many numbers there are. You may want to double check, but i got 2,080 for the first question.

To find median it it literally the number in the middle of the list, so for A, the median is 3, B’s median is 1, C is 3, and D is 2.

Range is the difference between the highest and lowest numbers, so you take the highest and subtract the lowest from it. The highest in all of these is 3, and the lowest is 1, so 3-1. The range for all of them is 2.

I hope this is helpful for you :-)

Let me know if any of this doesn’t make sense or if you need more help with it and I’ll comment:)

3 0

4 years ago

What is the measure of A?<br> (3y + 27)<br> What is the measure of B?<br> (5y - 3)

user100 [1]

Answer:

y=15

Step-by-step explanation:

3y+27=5y-3

27=2y-3

30=2y

y=15

Thats assuming A and B are equal ^

Hope this helps :)

4 0

3 years ago

Please no links

Nookie1986 [14]

Hey there!

-7x + 21 > -14

SUBTRACT 21 to BOTH SIDES

-7x + 21 - 21 > -14 - 21

SIMPLIFY IT!

NEW EQUATION: -7x > -35

DIVIDE -7 to BOTH SIDES

-7x/-7 > -35/-7

SIMPLIFY IT!

x < 5

Therefore, your answer is: x < 5

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

6 0

3 years ago

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t

motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

$99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = 15.5$

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = 0.4957$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where $\bar{x}$ is the sample mean and Margin of error is given by

$$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample size, s is the sample standard deviation and is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

$MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\$

So the required 99% confidence interval is

$\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0

4 years ago