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lapo4ka [179]
4 years ago
15

PLEASE HELP! What is the value of x in the proportion StartFraction 2 and one-fourth over x EndFraction = StartFraction 1 and on

e-half over 3 and three-fifths EndFraction?
A. 2 and two-fifths
B. 5 and two-fifths
C. 8 and StartFraction 1 over 10 EndFraction
D. 12 and StartFraction 3 over 20 EndFraction
Mathematics
2 answers:
AysviL [449]4 years ago
8 0
D. But I’m not 100% sure
romanna [79]4 years ago
5 0

Answer:

D. I think.

Step-by-step explanation:

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Arrange from least to greatest.<br> 5/6 2/4 5/12
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Answer:

5/6=10/12. 2/4=6/12. 5/12

5/12. 2/4. 5/6

6 0
3 years ago
Question<br>224 7/10 as decimal​
atroni [7]

Answer:

224 7/10 is a mixed fraction ..so first we convert it into an improper fraction ...

=> for that follow these steps ...

=> 224 X 10 + 7

=> 2247/10

so now to get in decimals ..we divide 2247 by 10..

=> 224.7 ...

so here we  got 224 7/10 in its decimal form ...

Step-by-step explanation:

hope that helps :))

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3 years ago
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The benchmark used to compare 9/8 and 11/12
olga nikolaevna [1]

Answer:

99/96

i hope is the answer


Step-by-step explanation:


7 0
4 years ago
Read 2 more answers
A university cafeteria line in the student center is a
nirvana33 [79]

Answer:

Lamda= 4 students/min, µ= 5 students/min  

P= Lamda/µ= 4/5= 0.8

a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2

b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5-  - .2 - (.8)*.2 – (.2)*.8^2))= 0.848

Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768

c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes

d.) L(q)= lamda*W(q)= 4*.8= 3.2 students

e.) L(System)= lamda/(µ-lamda)= 4 students.

f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.

P= 4/10= 0.4

Probability that system is empty= P0= 1-.4= 0.6

W(q)= 4/10(10-4)= 0.0667 minutes

L(q)= Lamda*W(q)= 4*.0667=0.2668

L(system)= Lamda/(µ-lamda)= 4/6= .667

Step-by-step explanation:

6 0
3 years ago
How many cubic feet are in 3 cubic yards
Mrrafil [7]
1 yard contains 3 feet. Then to find how many cubic feet are in 1 cubic yard you raise both to the power 3. this is: 1 yard = 3 feet => (1 yard)^3 = (3 feet)3 => 1 yard^3 = 27 feet^3. Now you have to multiply by 3 to get the number of cubic feet in three cubic yards => 3 * (1 yard^3) = 3 (27 feet^3) => 3 yard^3 = 81 feet^3, then <span>there are 81 cubic feet in 3 cubic yards.</span>
4 0
4 years ago
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