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Allisa [31]
3 years ago
6

Rule number one for handling an emergency is to _____. A. buy a new vehicle B. call law enforcement C. remain calm D. restart th

e vehicle
Computers and Technology
2 answers:
KengaRu [80]3 years ago
8 0

Answer:

Remain calm.

Explanation:

Keeping your calm can get you through any emergency situation.  Physical activity stimulates the vagus nerve (a part of the autonomic nervous system) that calms the body down, which is necessary for staying calm when under pressure. During a stressful situation, negative thoughts only work toward increasing your stress level and that is not good for your body or helpful in making effective decisions. This can help you feel like you are in control of the situation and ultimately face the emergency situation better.

marishachu [46]3 years ago
7 0
I believe the awnser is c! Hioe this helped!
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Select the proper ergonomic keyboarding techniques.
SCORPION-xisa [38]

Answer:

The correct options are;

-Position the keyboard directly in front and close to you so you don't have an excessive reach

-Keep your shoulders, arms, hands and fingers relaxed

-Position your wrists straight or in neutral position while typing

-Adjust your chair height and position so your feet rest flat on the floor, or add a footrest to compensate for a higher chair

-Adjust the keyboard height so that your shoulders can relax and your arms are straight in front of you

Explanation:

1) It is important to keep the fingers in a relaxed position when typing

2) Ensure to type in a tapping fashion when typing rather than pressing on the keys of the keyboard

3) The fingernails should be kept short when frequent typing is done

4) The wrist is better kept above the keyboard than resting on it

5) Ensure that the mouse is easily reached.

4 0
3 years ago
A ________________ uses multiple systems to attack one or more victim systems or websites with the intent of denying service to
Advocard [28]

Answer:

4. A Denial of Service attack (DDOS attack).

Explanation:

A DDOS attack is a malicious attempt to disrupt the normal traffic to a service.

In essence, it sends an enormous amount of requests to the service, until the server is overwhelmed because it can't handle that much traffic, and collapses in an overflow.

Thus, regular users are not able to access their services.

Usually, attackers use a botnet, a network of "zombie" computers that have been previously infected with a malware that allows the attacker to remotely control them, then the botnet starts to send a flood of traffic from different locations, and make the attacker difficult to detect or track.

6 0
4 years ago
Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
Disadvantages assembly level language for programming ​
Alisiya [41]
It takes a lot of time and effort to write the code for the same. It is very complex and difficult to understand. The syntax is difficult to remember. It has a lack of portability of program between different computer architectures.

Hope that helps
7 0
3 years ago
Read 2 more answers
Jim is in the market for a car that will last for the next 10 years and has saved up some money for the purpose of a car. What’s
Ratling [72]
I would imagine car would still be the best means , it's tough to define without knowing where he lives and how much he travels
8 0
3 years ago
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