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3 years ago

Who elso does their online school in their bed cause i do

Computers and Technology

2 answers:

Goshia [24]3 years ago

8 0

I do

it just feels right

Katen [24]3 years ago

3 0

Answer:

yeah same

Explanation:

You might be interested in

Match the parts of the website address with its correct explanation. http://www.usa.gov/Agencies/federal.shtml

storchak [24]

HTTP means Hyper Text Transfer Protocol underlying protocol used by the World Wide Web(www).

usa is the server name which is used address in the DNS record

.gov is the Domain names which are used to identify more then one IP addresses

Agencies/federal.shtml a directory is a collection of file resources also called the resource ID.

6 0

3 years ago

Read 2 more answers

Pls help help me is good help me helping is very good

skelet666 [1.2K]

Answer:

-56 negative

Explanation:

8 0

3 years ago

Hello, I've tried everything and I cannot get this code to be fair. I need help. Can someone provide guidance so I can understan

Liula [17]

A program that takes a date as input and outputs the date's season. The input is a string to represent the month and an int to represent the day is given below:

<h3>The Program</h3>

input_month = input()

input_day = int(input())

months= ('January', 'February','March', 'April' , 'May' , 'June' , 'July' , 'August' , 'September' , "October" , "November" , "December")

if not(input_month in months):

print("Invalid")

elif input_month == 'March':

if not(1<=input_day<=31):

print ("Invalid")

elif input_day<=19:

print("Winter")

else:

print ("Spring")

elif input_month == 'April' :

if not(1<=input_day<=30):

print("Invalid")

else:

print("Spring")

elif input_month == 'May':

if not(1<=input_day<=31):

print("Invalid")

else:

print("Spring")

elif input_month == 'June':

if not(1<=input_day<=30):

print("Invalid")

elif input_day<=20:

print ("Spring")

else:

print("Summer")

elif input_month == 'July' or 'August':

if not(1<=input_day<=31):

print("Invalid")

else:

print("Summer")

elif input_month == 'September':

if not(1<=input_day<=30):

print("Invalid")

elif input_day<=21:

print ("Summer")

else:

print ("Autumn")

elif input_month == "October":

if not(1<=input_day<=31):

print("Invalid")

else:

print("Autumn")

elif input_month == "November":

if not(1<=input_day<=30):

print("Invalid")

else:

print ("Autumn")

elif input_month == "December":

if not(1<=input_day<=31):

print("Invalid")

elif input_day <=20:

print ("Autumn")

else:

print ("Winter")

elif input_month == 'January':

if not(1<=input_day<=31):

print("Invalid")

else:

print("Winter")

elif input_month == "February":

if not(1<=input_day<=29):

print("Invalid")

else:

print ("Winter")

Read more about programming here:

brainly.com/question/23275071

#SPJ1

5 0

1 year ago

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

$v = \frac{(xf-xo)}{(t-to)}$

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

$t =\frac{xf}{v} =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.$

⇒ t = 8.7*10⁻⁴ sec.

4 0

3 years ago

Samuel was hired to create a program that asks the user questions and, based on the answers, recommend a book to read. What kind

quester [9]

Answer:

I think the answer is C

Explanation:

Selection

3 0

3 years ago