The most likely type of instruction that was executed by the CPU is: a jump instruction.
<h3>What is a CPU?</h3>
A central processing unit (CPU) can be defined as the main components of a computer because it acts as the brain of a computer and does all the processing and logical control.
This ultimately implies that, a central processing unit (CPU) is typically used by a computer to execute an instruction or set of instructions when powered on.
<h3>What is a
jump instruction?</h3>
In Computer technology, a jump instruction specifies an offset to a new place in the program sequence when processing an instruction or set of instructions in a computer.
Read more on CPU here: brainly.com/question/5430107
Answer:
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Explanation:
a
Answer:
A. OU
Explanation:
An organization unit (OU) is used to group objects that are related, having similar administrative and security requirements within a domain. It provides a way of classifying objects in a directory, such as differentiating between objects with the same name or managing and creating objects. An OU can be nested into another OU, thus it can be used to create a hierarchy within an organization.
Answer:
The correct answer to the following question will be "True".
Explanation:
SCADA is a hardware and software elements program that permits industrial enterprises to:
- Agricultural processes are regulated locally or globally.
- The human-machine interaction program specifically interfaces with equipment such as cameras, switches, generators, motors and much more.
- Track, store, and process the data in real-time.
Therefore, the given statement is true.
Answer:
A. 0.0450
B. 4
C. 0.25
D. 37.68
E. 6Hz
F. -0.523
G. 1.5m/s
H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
I. -1.67m/s.
Explanation:
Given the equation:
y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)
Standard wave equation:
y(x, t)=Asin(kx−ωt+ϕ)
a.) Amplitude = 0.0450
b.) Wave number = 1/ λ
λ=2π/k
From the equation k = 25.12
Wavelength(λ ) = 2π/25.12 = 0.25
Wave number (1/0.25) = 4
c.) Wavelength(λ ) = 2π/25.12 = 0.25
d.) Angular frequency(ω)
ωt = 37.68t
ω = 37.68
E.) Frequency (f)
ω = 2πf
f = ω/2π
f = 37.68/6.28
f = 6Hz
f.) Phase angle(ϕ) = -0.523
g.) Wave propagation speed :
ω/k=37.68/25.12=1.5m/s
h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.
