Answer:
Following are the code in the C Programming Language.
//set integer datatype variable
int score;
//check condition is the score is in the range of 0 to 100
if(score > 0 && score < 100){
//print if condition is true
printf("Valid test scores");
}else{
//otherwise print the following string.
printf("test scores are Invalid");
}
Explanation:
<u>Following are the description of the code.</u>
In the following code that is written in the C Programming Language.
- Set an integer data type variable i.e., score.
- Then, set the if conditional statement to check the condition is the variable "score" is greater than 0 and less the 100.
- If the following statement is true then print "Valid test scores".
- Otherwise, it print "test scores are Invalid".
Zebulon Pike, the U.S. Army officer who in 1805 led an exploring party in search of the source of the Mississippi River, sets off with a new expedition to explore the American Southwest. Pike was instructed to seek out headwaters of the Arkansas and Red rivers and to investigate Spanish settlements in New Mexico.
The answer is: [B]: " 2 " .
_____________________________________________
Explanation:
____________________________________
Given the chemical equation:
____________________________________
<u> ? </u> H₂ + O₂ → 2 H₂<span>O ;
____________________________________________
</span> → <span> We are asked, "What coefficient, if any — should be put in front of the: " H</span>₂ " ;
__________________________________________________
(which is on the "left-hand side" side of the chemical equation given— the "reactants") ;
→ to get a balanced chemical equation?
__________________________________________________
→ Let us examine the "right-hand side" of this chemical equation—the product(s). In this case, the "product" given is: " 2 H₂O " .
So, on the "right hand side", we have:
__________________________________________________
1) 4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ; <u><em>and</em></u>:
2) 2 "O's" → { Two "O's").
__________________________________________________
So, the left-hand side should have:
__________________________________________________
1) 4 "H's" ; <u><em>and</em></u>:
2) 2 "O's" ;
__________________________________________________
Let us examine the left-hand side (the "reactants").
__________________________________________________
" <u> ? </u><u /> H₂ + O₂ " ;
__________________________________________________
On the left-hand side, we already have:
__________________________________________________
1) " 2 O's " ; → one "O₂" = "2 O's" ; and:
2) "2 H's " ; → one "H<span>₂" .</span>
Now, we would need:
__________________________________________________
A "<u>total of "4 H's</u>". Is there any number we could put as a coefficient on the other reactant, which happens to be: "H₂" ; to make a <u><em>total of</em></u> "4 H's" ?
{Note: There are only these TWO (2) reactants in this chemical equation.}.
→ The "H₂" ; as it stands alone, is insufficient—since that would be only "2 H's".
__________________________________________________
→ Thus, we can rule out: "Answer choices: [A] and [D]."
___________________________________________________
<u>Note</u>:
→ Choice [A]: "1" ; The coefficient, "1"; is generally not (never?) used; and basically would function as the same as:
→ Choice: [D]: "<span>no coefficient is needed".
</span>→ <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
__________________________________________________
Since we are given: "H</span>₂" ; what coefficient could we put in front of this to get: "4 H's" ? (4÷2 =2). So we could put a "2" in front of the "H₂" ; to get:
"4 H's". The coefficient, "2" , corresponds directly with:
__________________________________________________
→ Answer choice: [B]: "2" .
_________________________________________________
{ <u>NOTE</u>: The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
_________________________________________________
So, the correctly balanced equation is:
2 H₂ + O₂ → 2 H₂O ;
_________________________________________________
→ The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is: "2" .
_________________________________________________
The correct answer is: [B]: "2" .
→ The coefficient that goes before the "H₂" is: "2" .
_________________________________________________
Hope this answer—and {lengthy} explanation—is of help!
_________________________________________________
