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Maslowich
3 years ago
12

A smaller number is 3 less than half a larger number. The larger number is 10 times 1 less than the smaller number. Let x repres

ent the smaller number, and let y represent the larger number. Which equations can be used to model the situation? Check all that apply. x = one-half y minus 3 2 x minus y = negative 6 2 x minus y = negative 3 x = one-half (y minus 3) y = 10 (x minus 1)
Mathematics
2 answers:
Zepler [3.9K]3 years ago
6 0

Answer:

Step-by-step explanation:

Represent the larger and the smaller numbers by y and x.  Then:

y = 10(x - 1) and x = (y/2) - 3

Alexeev081 [22]3 years ago
5 0

Answer:

its A, B, and E

Step-by-step explanation:

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Solve this system of equations
olga_2 [115]

Answer:

D) x = 4, y = -2, z = 3

Step-by-step explanation:

x = 3z − 5

2x + 2z = y + 16

2(3z - 5) + 2z = y + 16

6z - 10 + 2z = y + 16

8z = y + 26 ---> (A)

7x − 5z = 3y + 19

7(3z - 5) - 5z = 3y + 19

21z - 35 - 5z = 3y + 19

16z = 3y + 54 ---> (B)

8z = y + 26

16z = 3y + 54

2(y + 26) = 3y + 54

2y + 52 = 3y + 54

y = -2

8z = -2 + 26

8z = 24

z = 3

x = 3(3) - 5

x = 4

8 0
3 years ago
1+4=5<br> 2+5=12<br> 3+6=21<br> 8+11=
jek_recluse [69]
=12-5=7
=21-12=9
when u look at they have a diffrence of 2 so the answer will have a diffrence of 2 =11
8 0
4 years ago
A forest covers 43,000 acres. A survey finds that 0.7​% of the forest is​ old-growth trees. How many acres of​ old-growth trees
Goryan [66]

Answer:

301 acres

Step-by-step explanation:

43,000 acres of forest

0.7% is old-growth

0.7% = 0.007

43,000 * 0.007 = 301 acres

7 0
3 years ago
A culture of bacteria has an initial population of 650 bacteria and doubles every 9 hours. Using the formula Pt=P0⋅2tdP_t = P_0\
Ghella [55]
So is doubling, first off, meaning, if the current amount say P, then when it doubles is 2P, or double that, or P + P, so the rate of growth is 100%, since it's doubling.

and is doing it every 9 hour cycle, thus

\bf \textit{Periodic/Cyclical Exponential Growth}\\\\&#10;A=P(1 + r)^{\frac{t}{c}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{initial amount}\to &650\\&#10;r=rate\to 100\%\to \frac{100}{100}\to &1.00\\&#10;t=\textit{elapsed time}\to &10\\&#10;c=period\to &9&#10;\end{cases}&#10;\\\\\\&#10;A=650(1 + 1)^{\frac{10}{9}}\implies A=650(2)^{\frac{10}{9}}\implies A=650\sqrt[9]{2^{10}}
4 0
3 years ago
Please help give lots of points need please.
aleksandr82 [10.1K]

I think it might be grow. The slope is a positive number.

7 0
3 years ago
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