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Fofino [41]
2 years ago
10

What would the number, 4 tens + 3 + eight hundred thousand + 5000 look like?

Mathematics
2 answers:
MrMuchimi2 years ago
4 0
805,043 just add them
qwelly [4]2 years ago
3 0
805043 would be the answer i believe
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Find the volume of this irregular figure.
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I would say that the Answer is 35 I hope this isnt wrong..

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The factors of 55 are________________________________.I know that 55 is a (prime/composite) number because...
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Answer:

11 & 5 are the factors of 55

Step-by-step explanation:

Factors of 55

11 × 5 = 55

Thus, 11 & 5 are the factors of 55

 

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Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?
Oksanka [162]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  - 7 = 0

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  = 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 7 \div 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 1

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 0

8 0
2 years ago
A cardboard box without a lid is to have a volume of 19,652 cm3. Find the dimensions that minimize the amount of cardboard used.
Effectus [21]

Answer:

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

Step-by-step explanation:

Let the dimension of the cardboard box be x cm by y cm by z cm.

The surface area of the cardboard box without lid is

f(x,y,z)= xy+2xz+2yz.....(1)

Given that the volume of the cardboard is 19,652 cm³.

Therefore xyz =19,652

\Rightarrow z=\frac{19652}{xy}......(2)

putting the value of z in the equation (1)

f(x,y)=xy+2x(\frac{19652}{xy})+2y(\frac{19652}{xy})

\Rightarrow f(x,y)=xy+\frac{39304}{y})+\frac{39304}{x}

The partial derivatives are

f_x=y-\frac{39304}{x^2}

f_y=x-\frac{39304}{y^2}

To find the dimension of the box set the partial derivatives f_x=0 and f_y=0.Therefore y-\frac{39304}{x^2}=0

\Rightarrow y=\frac{39304}{x^2}.......(3)

and   x-\frac{39304}{y^2}=0

\Rightarrow x=\frac{39304}{y^2}.......(4)

Now putting the x in equation (3)

y =\frac {39304}{(\frac{39304}{y^2})^2}

\Rightarrow y=\frac{y^4}{39304}

\Rightarrow y^3= 39304

⇒y=34 cm

Then \Rightarrow x=\frac{39304}{34^2} =34 cm.

Putting the value of x and y in the equation (2)

z=\frac{19652}{34 \times 24}

  =17 cm.

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

4 0
3 years ago
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