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3 years ago

Does anyone know how to work this out?

Mathematics

2 answers:

frozen [14]3 years ago

5 0

Step-by-step explanation:

conditions : x≠0 and x≠-a and b≠1

1/(x+a) = b/x ⇌ 1×x = b(x+a) ⇌ x = bx + ba ⇌ (1-b)x = ab ⇌ x = ab/(1-b)

____ [38]3 years ago

4 0

I’m sorry I don’t know the answer I’m just trying to ask mine

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8. How many days would it take to travel from Washington, D.C.,

adell [148]

Answer:

What are the choices and what grade level going to 4th-12th

Step-by-step explanation:

7 0

3 years ago

What is the probability of tossing a coin three times and getting tails each time?

telo118 [61]

Answer:

1/8

Step-by-step explanation:

This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.

The probability of flipping tails is 1/2. We need three of these.

1/2 x 1/2 x 1/2 = 1/8

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2 years ago

What is the sum of the geometric sequence −4, 24, −144, ... if there are 8 terms?

Helga [31]

Answer:

The sum of 8 geometric sequence is 959780

Step-by-step explanation:

We are given

this sequence is geometric

-4 , 24 , -144

First term is -4

so, $a_1=-4$

now, we can find common ratio

$r=\frac{24}{-4}=-6$

we can use formula

$S_n=a_1(\frac{1-r^n}{1-r} )$

n=8

now, we can plug values

$S_8=-4(\frac{1-(-6)^{8}}{1+6} )$

now, we can simplify it

and we get

$S_8=959780$

4 0

3 years ago

Help me answer this pls

stira [4]

Answer:

x=5

Step-by-step explanation:

From this information we know that,

$5x - 6 = 3x + 4 \\ 5x - 3x = 4 + 6 \\ 2x = 10 \\ x = 5$

Hope it helps :)

6 0

3 years ago

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is <span>drag factor
</span> $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago