(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )
Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft
2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)
Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)
Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm
6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)
Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.
(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)
Answer:
.
Step-by-step explanation:
We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
Answer:
x = 6
Step-by-step explanation:
CT is a median, which means it divided AB into two equal parts so we can write the following equation:
7x + 9 = 5x + 21 transfer like terms to the same side of the equation
7x - 5x = 21 - 9 do the extraction
2x = 12 divide both sides by 2
<u>x = 6</u>
X = 5y + 30/4 - 3 is the answer.
