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Hitman42 [59]
3 years ago
7

Pls help me in this question

Mathematics
1 answer:
kari74 [83]3 years ago
4 0

Answer:

3

Step-by-step explanation:

since the diagonal are equal in length

6x-8=2x+4

4x=12

x=3

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Fynjy0 [20]
Xy=11
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x^2+26x+11=0

ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


a=1
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x=\frac{-26+/-\sqrt{26^{2}-4(1)(11)} }{2(1)}
x=\frac{-26+/-\sqrt{676-44} }{2}
x=\frac{-26+/-\sqrt{632} }{2}
x=\frac{-26+/-2\sqrt{158} }{2}
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