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Ira Lisetskai [31]
3 years ago
6

WILL MARK BRAINLEST PLEASE HELP

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer: it's 2/10

Step-by-step explanation:

kolbaska11 [484]3 years ago
5 0
Answer is A. 1/125 √3 1/125
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Solve the following system of linear equations.
Lisa [10]

Answer:

1 - x = 0.576066

2- x = varies you can either have '1' or you can have ' 0.387425886722...

3 - x = 0.762863

Step-by-step explanation:

3 0
4 years ago
What is the eleventh term in the sequence 17, 24, 31, 38…?
shusha [124]

Answer:

87

Explanation:

This is an arithmetic sequence with <u>common difference</u>: 7 and <u>first term</u>: 17

Arithmetic sequence:

a + (n - 1)d                    where n is term position, d is difference, a is first term

17 + (n - 1)7

7n + 10

The eleventh term:

7n + 10

7(11) + 10

77 + 10

87

6 0
2 years ago
Read 2 more answers
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
Can 403/72 be reduced?
tresset_1 [31]

Answer:

yes but it would be an incomplete fraction

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The vertice of triangle ABC are A(8,4), B(6,3) and C(5-5). Find the angle between the side AB and BC.​
Zigmanuir [339]

Answer:

Step-by-step explanation:

Use law of cosines

c² = a² + b² - 2abcosθ

cosθ = (c² - a² - b²) / -2ab

c = length of AC = √(8 - 5)² + (4 - (-5))² = √90

b = length of AB = √(8 - 6)² + (4 - 3)² = √5

a = length of BC = √(6 - 5)² + (3 - (-5))² = √65

cosθ = (√90² - √65² - √5²) / -2√65√5

cosθ = 20 / -36.05551...

cosθ = - 0.5547001

θ = 123.69°

7 0
3 years ago
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