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bixtya [17]
1 year ago
9

What is the eleventh term in the sequence 17, 24, 31, 38…?

Mathematics
2 answers:
shusha [124]1 year ago
6 0

Answer:

87

Explanation:

This is an arithmetic sequence with <u>common difference</u>: 7 and <u>first term</u>: 17

Arithmetic sequence:

a + (n - 1)d                    where n is term position, d is difference, a is first term

17 + (n - 1)7

7n + 10

The eleventh term:

7n + 10

7(11) + 10

77 + 10

87

Ymorist [56]1 year ago
6 0

<u>To Find :</u><u>-</u>

  • Eleventh term of the sequence.

<u>Solution</u><u> </u><u>:</u><u>-</u>

Given A.P.,

  • 17 , 24 , 31 , 38 …

First term (a) is 17.

Common difference (d) = 24 - 17 => 7

We know that :

  • tn = a + (n - 1) d

Here n would be 11.

>> t11 = 17 + (11 - 1) 7

>> t11 = 17 + (10) 7

>> t11 = 17 + (10) × 7

>> t11 = 17 + 70

>> t11 = 87

Therefore, eleventh term in the sequence is 87.

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Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

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and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

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Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

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