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Yuki888 [10]
3 years ago
10

Can anyone do this quickly since I’m being timed again

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

Answer:

x = 31

Step-by-step explanation:

2x + (3x + 25) = 180

5x + 25 = 180

5x = 155

x = 31

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Help me please please please please
Oxana [17]

Answer:

1.

d. (-14) + (-8)

2.

a. (-14) + 8

Step-by-step explanation:

(-14) - 8 is equal to (-14) + (-8) because we still add two negative values so the result wouldn't change.

(-14) - (-8) is equal to (-14) + 8 because there's two negative sign in front of 8 and two negative values multiplied makes a positive result.

6 0
3 years ago
Read 2 more answers
Brainly!
bezimeni [28]

Answer:

1/15

Step-by-step explanation:

There are a total of 10 fruits, 3 of which are apples.

The probability that the first selection is an apple is 3/10.

There are now 9 fruits remaining, 2 of which are apples.  So the probability that the second fruit is an apple is 2/9.

The total probability is (3/10) (2/9) = 1/15.

5 0
3 years ago
Can someone help me please
Novosadov [1.4K]

Answer:

Substitute the 80°F where the F is in the equation. then just put the whole equation into your calculator. I got approximately 26.7.

4 0
3 years ago
(5 – 3x)4 – 2<br><br> Please I need help. Show steps im so confused
RSB [31]

Answer:

6

Step-by-step explanation:

P (5-3) =2

E X

M 2 x 4 =8

D X

A X

S 8 - 2 =6

6 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
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