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storchak [24]
3 years ago
6

A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ

ate is $600 and the daily rate for each partner is $1100. The law firm assigned a total of 10 lawyers to the case and was able to charge the client $8000 per day for these lawyers' services. Determine the number of associates assigned to the case and the number of partners assigned to the case.
There were ____associates assigned to the case and ____
partners assigned to the case.
Mathematics
1 answer:
Tom [10]3 years ago
6 0

Answer:   x = 7

Thus 7 associates and 10 partners were assigned

Step-by-step explanation:

7 associates and 10 partners were assigned

Let "x" be the number of associates assigned to

case

Let "y" be the number of partners assigned to the case

The law firm assigned a total of 17 lawyers to the case

Therefore,

x + y = 17

x = 17 - y --------- eqn 1

daily rate charged to the client for each associate is $800

daily rate for each partner is $1800

They was able to charge the client $23600 per day for these lawyers' services

Therefore,

800x + 1800y = 23600 ------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

800(17 - y) + 1800y = 23600

13600 - 800y + 1800y = 23600

1000y = 23600 - 13600

1000y = 10000

Divide both sides by 1000

y = 10

Substitute y = 10 in eqn 1

x = 17 - 10

x = 7

Thus 7 associates and 10 partners were assigned

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Answer:

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Step-by-step explanation:

we know that

To find the unit rates divide the total cost by the total volume

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(6/54)=0.11 $/ounce

5 0
3 years ago
Given right triangle ABC, with altitude CD intersecting AB at point D. If AD = 5 and DB = 8, find the length of CD, in simplest
galben [10]

First we dra a triangle:

To prove that the triangles are similar we have to do the following:

Considet triangles ABC and ACD, in this case we notice that angles ACB and ADC are equal to 90°, hence they are congruent. Furthermore angles CAD and CAB are also congruent, this means that the remaining angle in both triangles will also be congruent, therefore by the AA postulate for similarity we conclude that:

\Delta ABC\approx\Delta ACD

Now consider triangles ABC and BCD, in this case we notice that angles ACB and BDC are congruent since they are both equal to 90°. Furthermore angles ABC and DBC are also congruent, this means that the remaining angle in both triangles will, once again, be congruent. Hence by the AA postulate we conclude that:

\Delta ABC\approx\Delta BCD

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\Delta ACD\approx BCD

Now that we know that both triangles are similar we can use the following proportion:

\frac{h}{x}=\frac{y}{h}

this comes from the fact that the ratios should be the same in similar triangles.

From this equation we can find h:

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Plugging the values we have for x and y we have that h (that is the segment CD) has length:

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6 0
2 years ago
Two independent samples of sizes 20 and 30 are randomly selected from two normally distributed populations. Assume that the popu
aleksley [76]

Answer:

b. Student-t with 48 degrees of freedom

Step-by-step explanation:

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Assumptions

When running a two-sample equal-variance t-test, the basic assumptions are "that the distributions of the two  populations are normal, and that the variances of the two distributions are the same".

Let \bar x and \bar y be the sample means of two sets of data of size n_x and n_y respectively. We assume that the distribution's of x and y are:

x \sim N(\mu_x ,\sigma_x =\sigma)

y \sim N(\mu_y ,\sigma_y=\sigma)

Both are normally distributed but without the variance equal for both populations.

The system of hypothesis can be:

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Alternative hypothesis: \mu_x \neq \mu_y

We can define the following random variable:

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So on this case the best answer would be :

b. Student-t with 48 degrees of freedom

5 0
3 years ago
Please help with this thank you
melamori03 [73]

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Answer:

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