The volume of the pyramid would be 2406.16 cubic cm.
<h3>How to find the volume of a square-based right pyramid?</h3>
Supposing that:
The length of the sides of the square base of the pyramid has = b units
The height of the considered square-based pyramid = h units,
The pyramid below has a square base.
h = 24.4 cm
b = 17.2 cm
Then, its volume is given by:


Therefore, the volume of the pyramid would be 2406.16 cubic cm.
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Answer:
x(x^2+2)^3/2
Step-by-step explanation:
y'=1/2(x^2+2)^3/2.2x
= x(x^2+2)^3/2
Answer:
False
Step-by-step explanation:
If the triangle is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
9^2 + 22^2 = 24^2
81+484=576
565 = 576
This is false, so the triangle is not a right triangle
<span> To </span>find the area<span> of a </span>regular polygon<span>, all you have to do is follow this simple formula: </span>area<span> = 1/2 x perimeter x </span>apothem<span>. Here is what it means: Perimeter = the sum of the lengths of all the sides.</span>
Step-by-step explanation:
the two alternate interior angles are Angle GHE and DEH