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3 years ago

What's the measure of Z1 if Z CBD = 75° and ZABC = 135°?

Mathematics

2 answers:

svet-max [94.6K]3 years ago

6 0

Answer:

Brainliest goes to me!

Step-by-step explanation:

angle abc = 135 degrees

part of it is angle 1 and the other part is angle cbd

<abc (135) = cbd (75) + <1

angle 1 = 60 degrees

Paladinen [302]3 years ago

4 0

Answer:

60°

Step-by-step explanation:

∠ABC-∠CBD=∠1

$135-75$

$=60$

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The probability that John receives junk mail is 11 percent. If he receives 94 pieces of mail in a week, about how many of them c

SVETLANKA909090 [29]

Answer:

10 (10.34 rounded down)

Step-by-step explanation:

11% is the same as .11

Multiply by 94 for your answer.

.11 x 94 = 10.34

10 pieces

5 0

3 years ago

What value is added to both sides of the equation x2 − 8x = −10 in order to solve by completing the square?−816−44?

Artyom0805 [142]

Do you see -8x?

Take half of -8 and square it.

So, (-8)/2 = -4.

(-4)^2 = 16

Now add 16 to both sides.

6 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago

NEED HELP!!!!!EMERGENCY

Basile [38]

Answer:

49.5 square inches

Step-by-step explanation:

We can split the figure into two easier shapes to find the area of; a triangle and a square.

The formula for a triangle is (b*h)1/2. Once we solve we get 24.5 or 24 1/2.

The formula for a square is l*w. Once we solve we get 25.

To find the area of the shaded region, we would add both area and get 49.5 or 49 1/2 square inches.

8 0

3 years ago

Complete the statement 36x^3a+45xa^2=9xa

Lorico [155]

<span>36x³a + 45xa² =</span>9xa(4x²+5a)

7 0

3 years ago