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3 years ago

Orden the Numbers 0.78, 3/4, and 0.8 from last to greaters

Mathematics

1 answer:

OlgaM077 [116]3 years ago

7 0

Answer:

3/4, 0.78, 0.8

Step-by-step explanation:

3/4= 0.75.

0.78 is greater and 0.8 is greater again.

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At a summer camp there is one counselor for every 5 campers. Determine whether there is a direct variation between the number of

adell [148]

Campers = y and counselors = x.....1 counselor to 5 campers

y = kx
k = y/x
k = 5/1

y = 5x

lets check..
y = 5x....lets say u have 2 counselors...sub in 2 for x
y = 5(2)
y = 10....so when there is 2 counselors, there are 10 campers

y = 5x...lets say u have 3 counselors...sub in 3 for x
y = 5(3)
y = 15...so when there are 3 counselors, there are 15 campers

2/10 reduces to 1/5
3/15 reduces to 1/5

so yes, this is a direct variation with ur equation being y = 5x

5 0

3 years ago

8a+6ab+5b,-6a-ab-8b and - 4a+2ab+3b<br><br>Pls answer this question

suter [353]

Answer:

4 a+8 ab+8b

Step-by-step explanation:

8 a-4 a+6ab+2ab+5 b+3 b

4 a+8 ab+8b

6 0

3 years ago

A jawbreaker candy machine has 25 red jawbreakers, 30 green jawbreakers, 15 yellow

MArishka [77]

<h3>Answer: Choice C, 2/3</h3>

============================================

Work Shown:

A = # of candies that are not green

A = (# of red)+(# of yellow)+(# of blue)

A = 25+15+20

A = 60

B = # of candies total

B = (# of red)+(# of green)+(# of yellow)+(# of blue)

B = 25+30+15+20

B = 90

P(not green) = probability of selecting candy that is not green

P(not green) = (# of candies not green)/(# of candies total)

P(not green) = A/B

P(not green) = 60/90

P(not green) = (2*30)/(3*30)

P(not green) = 2/3

7 0

3 years ago

Chin researched the amount of money 150 students earned per month from jobs held during the summer. He created a table of six sa

dem82 [27]

the choices are below

the predicted mean of the population will be less than 200.

The predicted mean of the population will be less than 245.

The predicted mean of the population will be more than 275.

The predicted mean of the population will be more than 250.

b is the answer

8 0

3 years ago

Read 2 more answers

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago