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guajiro [1.7K]
3 years ago
9

Please help due tommorow

Mathematics
2 answers:
raketka [301]3 years ago
5 0

Answer:

4 is b 0.15

i think 5 is b

Step-by-step explanation:

i couldn't figure out the others "-u-

OlgaM077 [116]3 years ago
4 0
I think 1. Is 22 and 3. Is d
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Solve for x: |4x + 12| = 16
pentagon [3]
To solve
if you have |a|=b, solve a=b and a=-b

|4x+12|=16
solve
4x+12=16 and 4x+12=-16
minus 12 both sides
4x=4 and 4x=-28
divide both sides by 4
x=1 and x=-7
4 0
3 years ago
Read 2 more answers
Find the value of x. Round the length to nearest tenth.
Lady_Fox [76]

From the law of sines, we have

l = h\sin(\theta) = h\cos(\alpha)

where l is the leg we're interested in, h is the hypothenuse, \theta is the angle opposite to l, and \alpha is the angle between l and h.

So, in the first case, we can use

x = 15\sin(35) \approx 8.6

And in the second excercise, we use

x = 11\cos(44) \approx 7.6

5 0
3 years ago
Read 2 more answers
72 + 24 (distributive property)
Dmitrij [34]
The answers is 96
Dont u just add?
8 0
2 years ago
Factorize the following algebraic expression:
Hoochie [10]
X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x=\frac{ -b+\sqrt{b^2-4ac} }{2a} or x=\frac{ -b-\sqrt{b^2-4ac} }{2a}

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
\frac{ -16+\sqrt{16^2-4(1)(-38)} }{2(1)}=\frac{ -16+\sqrt{256+152} }{2}= \frac{ -16+\sqrt{408} }{2}= \frac{ -16+2\sqrt{102} }{2}=-8+\sqrt{102}
so the answers for x are -8+\sqrt{102} and -8-\sqrt{102}  which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0


6 0
3 years ago
Is 8/6 greater than or less than 11/12
Zanzabum
\frac{8}{6}\ \ \ \ and\ \ \ \ \frac{11}{12}\ \ \ \ \ | make\ a\ common\ denominator\ 12\\\\
\frac{16}{12}\ \ \ and\ \ \ \ \frac{11}{12}\\\\
Now\ it\ is\ visible\ that\ \frac{16}{12} \ >\ \frac{11}{12}\ so\ \frac{8}{6} \ >\ \frac{11}{12}\ 

8 0
4 years ago
Read 2 more answers
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