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3 years ago

7

It took Jane 1 hour and 20 minutes to do her math homework while it took Ava just 45 minutes. Find the ratio of time it took Jan

e to do her homework to the time it took Ava to do hers.

1 answer:

Zinaida [17]3 years ago

7 0

Answer:

9:16

Step-by-step explanation:

so the ratio is 1hr 20min to 45 min which is the same as saying 80 min(because an hour is 60 min) to 45 min. now we simplify both by 5 to get 9:16

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Answer:

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Step-by-step explanation:

Given:

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Now for a vector (x,y)

$\alpha =tan^{-1}(\frac{y}{x} )$ ; and

$v=\sqrt{x^2+y^2}$

Therefore:

$150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}$

$y=-\frac{x \sqrt{3}}{3}$

Similarly:

$v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2$

$144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}$

Recall that:

$y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3} \sqrt{3}}{3}=-6$

Therefore: $(x,y)=(6\sqrt{3}, -6)$

The vector in the form ai+bj is therefore:

$6\sqrt{3}i-6j$

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