What is 3 x 3 will mark brainliest

Solve and/or check.<br><br> |20x| = |4x + 16|

AfilCa [17]

Answer:

Step-by-step explanation:

|20x|=|4x+16|

or, 20x-4x=16

or, 16x=16

Hence, x=1

7 0

2 years ago

0+4=?<br> Help will be needed here

Romashka [77]

Answer:

40

you add a 0 to the four and boom

If you are really asking, then the answer is still 4

8 0

3 years ago

Read 2 more answers

Write the number and the nature of the roots of the quadratic equation whose discriminant is -12

Orlov [11]

Hello
<span>D. 2 imaginary roots (complex conjugates)</span>

7 0

3 years ago

A regression of y = calcium content (g/L) on x = dissolved material (mg/cm2) was reported in the article "Use of Fly Ash or Sili

MatroZZZ [7]

Answer:

a) The slope = 0.144 , means that an increase in dissolved material by 1 mg/cm^2 will lead to an increase in Calcium content by 0.144 g/l

while the coefficient of determination = 0.869 , means that 86% of the variation ( natural ) of calcium content is explainable using the Linear model.

b) 10.878

c) S ≈ 1.99

Step-by-step explanation:

a) The slope = 0.144 , means that an increase in dissolved material by 1 mg/cm^2 will lead to an increase in Calcium content by 0.144 g/l

while the coefficient of determination = 0.869 , means that 86% of the variation ( natural ) of calcium content is explainable using the Linear model.

<u>B) Point estimate of true average calcium content </u>

Given that dissolved material = 50 mg/cm^2

= 3.678 + 0.144 * dissolved material

= 3.678 + 7.2 = 10.878

<u>C) Determine an estimate of error standard deviation </u>

Given that ; sum of squares ( SST ) = 320.398

COD ( r ) = 0.86

first; calculate the value of SSE = SST - SST ( r^2 )

SSE = 320.398 - 320.398 ( 0.86) ^2

= 83.43

Finally ; determine the estimate of error standard deviation

S^2 = SSE / n -2

= 83.43 / 23 - 2

∴ S ≈ 1.99

6 0

3 years ago

Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will

VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

$A = P\left(1 + \dfrac{r}{n}\right)^{nt}$

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

$\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\$

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

$\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\$

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

7 0

3 years ago