All categories

3 years ago

Help!! YEEEEEEEEEEEEEEEEEET

Mathematics

1 answer:

timofeeve [1]3 years ago

3 0

Answer:

Step-by-step explanation:

Degree of quadratic equation is 2

So, y = (x + 2)² - 6 ; y = x² - 4x + 2 & y = -(x -2)² + 5 are quadratic equation

(a + b)² = a² + 2ab + b²

y = (x + 2)² - 6

y = x² + 2*x*2 + 2² -6

y= x² + 4x + 4 -6

y= x² + 4x - 2

Degree = 2

y = -(x - 2)² + 5

y = -[ x² - 2*x*2 + 2²] + 5

y = -[x² - 4x + 4)+5

y = -x² + 4x - 4 + 5

y = -x² + 4x + 1

Degree = 2

You might be interested in

What is the HCF of 66, 121 ,132

gayaneshka [121]

11

66=11×6
121=11×11
132=11×12

5 0

3 years ago

Read 2 more answers

Find the value of the underlined number 789,233 the 8 is underline

Fiesta28 [93]

7: hundred thousands
8: ten thousands
9: thousands
2: hundreds
3: tens
3: digits

8 0

4 years ago

Read 2 more answers

A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c

Anna [14]

Answer:

The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

Here assume that $Z_{\frac{\alpha }{2} } \ and \ \sigma \$ is constant so

$E = \frac{k}{\sqrt{n} }$

=> $E \sqrt{n} = K$

=> $E_1 \sqrt{n}_1 = E_2 \sqrt{n}_2$

So let $n_1 = 400$ and $n_2 = 100$

=> $E_1 \sqrt{400} = E_2 \sqrt{100}$

=> $E_1 = \frac{\sqrt{100} }{\sqrt{400} } E_2$

=> $E_1 = \frac{1}{2 } E_2$

So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100

7 0

3 years ago

X + 15 - 4<br> Please help ty

IrinaK [193]

$x+15-4 \\ \\ =x+11$

4 0

3 years ago

Jessica wants to calculate her grade in her accounting class.she has four test grades (82, 65, 71, and 77) and a homework grade

Aleks04 [339]

To solve the problem, get the percentage of each test by multiplying the score and the percentage then add it all up:

82 * .25 (highest test grade) + 65* .15 (lowest test grade) + 71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework grade)

= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number

3 0

4 years ago