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Paladinen [302]
3 years ago
8

(2.5-6.7)^2÷2/5 simplify. ​

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Answer

44.1

Step-by-step explanation:

(-4.2)^2/2/5

17.64/2/5

44.1

Svet_ta [14]3 years ago
6 0
The answer is 88.2 I believe
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The lines a and b intersect at point C.<br><br> What is the value of y?
Amanda [17]

Using the definition of vertical angles, the value of z is: 15.

<h3>Vertical Angles Pair</h3>

The two pairs of opposite angles formed when two straight lines intersect are called vertical angles, and are therefore congruent to each other.

Thus:

2z + 10 = 40

2z = 40 - 10

2z = 30

z = 30/2

z = 15

Therefore, using the definition of vertical angles, the value of z is: 15.

Learn more about vertical angles on:

brainly.com/question/1673457

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Answer:

Step-by-step explanation:

The answer is no solution or a 0 with a line through it

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In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

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3 years ago
Paige earned $15.50 per hour. She received a 10% raise. Paige worked 10 hours at her new salary. How much did Paige earn?
PSYCHO15rus [73]

Answer:

C- $170.50

Step-by-step explanation:

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