Question

Listed below are the annual tuition amounts of the 10 most expensive colleges in a country for a recent year.

Answer 1

Answer:

$\bar X = \frac{52384 +54079 +52762 +54364 +52584+53987 +53108 +51588 +50554 +53987}{10}=52939.7$

$Mode= 53987$

$Median = \frac{52762+53108}{2}=52935$

$Midrange=\frac{50554+54364}{2}=52459$

Step-by-step explanation:

We can calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace the values given we got:

$\bar X = \frac{52384 +54079 +52762 +54364 +52584+53987 +53108 +51588 +50554 +53987}{10}=52939.7$

The mode is the most repeated value and for this case with a frequency of 2 the mode is:

$Mode= 53987$

In order to find the median we need to order the dataset on increasing way like this:

50554, 51588, 52384  ,52584, 52762

53108, 53987 , 53987 , 54079, 54364

Since we have 10 values an even number the median is calculated from the average between positions 5 and 6 on the data ordered, and we got:

$Median = \frac{52762+53108}{2}=52935$

The mid range is defined like this:

$Midrange = \frac{Max +Min}{2}$

And if we replace we got:

$Midrange=\frac{50554+54364}{2}=52459$