I did this problem last year, if I remember you do this:
64 pounds of gravel and <span>108 pounds of mulch will be the outcome
</span>
*2 1/4 will be equal to 2.25
*1 1/3 will be equal to 1.33
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2.25 / 1.33 = 1.7 is fine (rounded up)
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*ratio of gravel = 1.7: 1
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FOR MULCH:
1.7/2.7 from 172 you will use the outcome 0.629 * 172 to get 108.2 pounds
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FOR GRAVEL:
172 - 108.2 = 63.8 pounds
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Totals sold will be:
- 108 Pounds
- 64 Pounds
<span>Since it is a projectile motion then I will go up then it
will go down once it reach the maximum height. as we can se from the table, the maximum height is 7 ft and it goes
down 6 ft then 4, so it should be the same as it goes up so A = 4 and B = 3</span>
Answer:
33.7º
Step-by-step explanation:
tan = opp/adj
tan∅ = 100/150 = 2/3
∅ = arctan 2/3
∅ = 33.690067525979787
33.7º
Answer:
a and d = 32
Step-by-step explanation:
since ABC and DEF are similar m<A = m<D so you have the equation
5x + 12 = 8x
subtract 8x from both sides
5x + 12 -8x = 0
subtract 12 from both sides
5x -8x = -12
combine like terms
-3x = -12
devide by -3
x = 4
plug 4 into equation
5(4) + 12 = 8*4
20 + 12 = 32
32 = 32
Answer:
please give me a brainless 0
Inequality :
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
The following is as far as I get:
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1
n−1−(⌊n÷m⌋×(a−b))≥x−α1a
n−(⌊n÷m⌋×(a−b))≥x−α1a + 1
Step-by-step explanation: