Answer:
500
Step-by-step explanation:
I will assume that you meant:
(x+4)/(-3x^2+12x+36) factor the denominator...
(x+4)/(-3(x^2-4x-12))
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=-12 and j+k=b=-4 so j and k must be 2 and -6 and the factors are then:
(x+2)(x-6) so we are now left with:
(x+4)/(-3(x+2)(x-6))
The only restriction on this function is that division by zero is undefined, so x cannot equal -2 or 6
Answer:
i would say C
Step-by-step explanation:
AA = $1
AAA= $0.75
AA + AAA = 42
$1AA + $0.75AAA= $37
AA + AAA = 42
AA + AAA-AAA= 42- AAA
AA = 42- AAA
$1(42- AAA) + $0.75AAA= $37
$42 - AAA +0.75AAA = $37
$42 -0.25AAA= $37
$42-$42 -0.25AAA= $37 -$42
-0.25AAA= -5
-0.25AAA/-0.25 = -5/-0.25
AAA= 20
AA + AAA= 42
AA + 20 = 42
AA +20 -20 = 42-20
AA= 22
Check
$1AA + $0.75AAA= $37
$1(22)+ $0.75(20)= $37
$22 + $15 =$37
$37 = $37
Answer:
21.90890230 or 21.91 (I'm assuming you're saying 120/ √30)
Step-by-step explanation:
