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3 years ago

Find the value of y in the rhombus below

Mathematics

1 answer:

jonny [76]3 years ago

8 0

All of a "rhombus's" sides are equal so if it states " one side is 30*" then all 4 sides are 30* .

If they are asking for the inside (perimeter) than you would have to divide 30* by 4 which leaves you with 7.5 .

To check your answer complete 7.5 x 4 and you'd get 30 .

(PLEASE MARK BRAINLIEST) :)

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PLEASE HELP 100 POINTS!!! The function f(x)=12sin(x−π4) is used to describe a water wave. The value x is the time in seconds, an

Otrada [13]

Answer:

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2 years ago

2. A chemist has a 25% and a 50% acid solution. How

AnnZ [28]

Answer:

x is mL of 25% acid and y is mL of 50% acid

We set up 2 equations:

A) x + y = 250

B) .25 x + .50y = .35 * 250 which equals

B) .25x + .50y = 87.50 Multiplying A) by -.5

A) -.5x -.5y = -125 adding the equations we get

-.25x = -37.50

x = 150 mL

y = 100 mL

Source: http://www.1728.org/mixture.htm

Step-by-step explanation:

7 0

3 years ago

Create a word problem that involves speed

lana66690 [7]

A hockey puck is sliding on frictionless ice on an infinite hockey rink.
Its speed is 36 km/hour. How far does the puck slide in 10 seconds ?

(36 km/hr) x (1,000 m/km) x (1 hr/3600 sec) x (10sec) =

(36 x 1,000 x 10 / 3,600) meters = <em>100 meters</em>

What is the puck's speed in miles per hour ?

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6 0

3 years ago

Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask

Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

$P(x=r)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

$P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}$

$=56(0.4)^5 (0.6)^3$

$=0.12386304$

(b) the probability of the number that say they would feel secure is more than five

$P(X>5) = P(X=6)+ P(X=7) + P(X=8)$

$=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}$

$=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8$

$=0.04980736$

(c) the probability of the number that say they would feel secure is at most five

$P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)$

$=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}$