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2 years ago

If 3a=11b and b= 2c, find the ratio of a:b, a:b:c

Mathematics

1 answer:

pav-90 [236]2 years ago

5 0

Answer:

a:b = 11:3 and a:b:c = 11:3:2

Step-by-step explanation:

a:b is equal than write a/b. So a/b=11/3 it means a:b = 11:3

b:c is then b/c = 2

For a:b:c the ratio must be maintained. Ratio is equals reasons or divides. We already know a:b is 11:3. What about a:c?

3a=11b then a=11/3 b, b=2c then c=1/2 b hence a/c =22/3 if we pay attention this reason is 2*11/3 so a:b:c is 11:3:2

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Answer:

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Step-by-step explanation:

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3 years ago

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andriy [413]

Area of the figure = 30.28 m²

Solution:

The given image is splitted into two shapes.

One is rectangle and the other is semi-circle.

Length of the rectangle = 6 m

Width of the rectangle = 4 m

Area of the rectangle = length × width

= 6 m × 4 m

= 24 m²

Area of the rectangle = 24 m²

Diameter of the semi-circle = 4 m

Radius of the semi-circle = 4 m ÷ 2 = 2 m

Area of the semi-circle = $\frac{1}{2} \ \pi r^2$

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3 years ago

What is the volume of the composite figure shown below?

AVprozaik [17]

Answer:

2412 mm³

Step-by-step explanation:

In the figure attached, the composite figure is shown.

Dimension of top rectangular prism:

length of 13 millimeters

width of 12 millimeters

height of 12 millimeters

Volume of top rectangular prism: length*width*height = 13*12*12 = 1872 mm³

Dimension of bottom rectangular prism:

length of 15 millimeters

width of 12 millimeters

height of 3 millimeters

Volume of bottom rectangular prism: length*width*height = 15*12*3 = 540 mm³

Volume of the composite figure: 1872 + 540 = 2412 mm³

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