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2 years ago

If 3a=11b and b= 2c, find the ratio of a:b, a:b:c

Mathematics

1 answer:

pav-90 [236]2 years ago

5 0

Answer:

a:b = 11:3 and a:b:c = 11:3:2

Step-by-step explanation:

a:b is equal than write a/b. So a/b=11/3 it means a:b = 11:3

b:c is then b/c = 2

For a:b:c the ratio must be maintained. Ratio is equals reasons or divides. We already know a:b is 11:3. What about a:c?

3a=11b then a=11/3 b, b=2c then c=1/2 b hence a/c =22/3 if we pay attention this reason is 2*11/3 so a:b:c is 11:3:2

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10x -15x + 5= -45 + 20

denpristay [2]

Answer:

x=6

Step-by-step explanation:

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2 years ago

Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x)

tamaranim1 [39]

Answer:

Step-by-step explanation:

3 $x^{2}$ +x-3= $x^{2}$ - 5x

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3 years ago

if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?

Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 9 rolls, hence $n = 9$ .

Of the six sides, 2 are 3 or 4, hence $p = \frac{2}{6} = 0.3333$

The desired probability is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026$

$P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117$

Then:

$P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857$

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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2 years ago

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NeTakaya

Hi

The answer is : 14s^133t^5u^144v^2

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3 years ago

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sashaice [31]

The one that has -7 and -13 on the first line.

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2 years ago